Code Snippet: User Input-Single Line

From Coder Merlin
Within these castle walls be forged Mavens of Computer Science ...
— Merlin, The Coder

Reading a single line of text from the console[edit]

Note: Input read from the console is terminated with a ^D (Control-D) which indicates the end-of-file.


// Read a single line of input from the console
let line = readLine()            // This will return an optional string
if line != nil {                 // Let's check if it's not nil, if so, it's really a string
    let text = line!             // Unwrap the string
    print("You typed: \(text)")  // Print the string
// Read a single line of input from the console (syntactic sugar)
if let text = readLine() {
    print("You typed: \(text)")


    text = input()
    text = ""
print("You typed: %s" %text)


my $input = <STDIN>;

print "You typed: $input";


#include <stdio.h>

int main(void){

  char line_buffer[64]; // Declare character array capable of holding 63 characters

  // Read input from stdin via fgets
  // check fgets return for NULL if EOF is passed
  if(fgets(line_buffer,64,stdin) == NULL){
    return 0; // Indicate successful run to the OS
  printf("You typed: %s\n",line_buffer); //Output input

  return 0; // Indicate a successful run to the OS


#include <iostream>
#include <string>

int main() {
    std::string input;
    std::getline(std::cin, input);
    if (! {
      std::cout << "You typed: " << input;
    return 0;

Common Lisp[edit]

(defvar input)

(setq input (read-line))

(format t "You typed: ~(~s~) ~%"


text = gets
puts "You typed: " + text